Integrand size = 26, antiderivative size = 69 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=\frac {x}{a^2 c}+\frac {\cot (e+f x) (3-2 \sec (e+f x))}{3 a^2 c f}-\frac {\cot ^3(e+f x) (1-\sec (e+f x))}{3 a^2 c f} \]
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Time = 0.15 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {3989, 3967, 8} \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=-\frac {\cot ^3(e+f x) (1-\sec (e+f x))}{3 a^2 c f}+\frac {\cot (e+f x) (3-2 \sec (e+f x))}{3 a^2 c f}+\frac {x}{a^2 c} \]
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Rule 8
Rule 3967
Rule 3989
Rubi steps \begin{align*} \text {integral}& = \frac {\int \cot ^4(e+f x) (c-c \sec (e+f x)) \, dx}{a^2 c^2} \\ & = -\frac {\cot ^3(e+f x) (1-\sec (e+f x))}{3 a^2 c f}+\frac {\int \cot ^2(e+f x) (-3 c+2 c \sec (e+f x)) \, dx}{3 a^2 c^2} \\ & = \frac {\cot (e+f x) (3-2 \sec (e+f x))}{3 a^2 c f}-\frac {\cot ^3(e+f x) (1-\sec (e+f x))}{3 a^2 c f}+\frac {\int 3 c \, dx}{3 a^2 c^2} \\ & = \frac {x}{a^2 c}+\frac {\cot (e+f x) (3-2 \sec (e+f x))}{3 a^2 c f}-\frac {\cot ^3(e+f x) (1-\sec (e+f x))}{3 a^2 c f} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.76 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.84 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=-\frac {\cot ^3(e+f x) \left (\operatorname {Hypergeometric2F1}\left (-\frac {3}{2},1,-\frac {1}{2},-\tan ^2(e+f x)\right )-3 \sec (e+f x)+2 \sec ^3(e+f x)\right )}{3 a^2 c f} \]
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Time = 0.55 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.72
method | result | size |
parallelrisch | \(\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}+12 f x -12 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+3 \cot \left (\frac {f x}{2}+\frac {e}{2}\right )}{12 a^{2} c f}\) | \(50\) |
derivativedivides | \(\frac {\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}{3}-4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+8 \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {1}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}}{4 f \,a^{2} c}\) | \(60\) |
default | \(\frac {\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}{3}-4 \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+8 \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {1}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}}{4 f \,a^{2} c}\) | \(60\) |
risch | \(\frac {x}{a^{2} c}-\frac {2 i \left (3 \,{\mathrm e}^{3 i \left (f x +e \right )}-5 \,{\mathrm e}^{i \left (f x +e \right )}-4\right )}{3 f \,a^{2} c \left ({\mathrm e}^{i \left (f x +e \right )}+1\right )^{3} \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}\) | \(72\) |
norman | \(\frac {\frac {x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{c a}+\frac {1}{4 a c f}-\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}}{a c f}+\frac {\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{4}}{12 a c f}}{a \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}\) | \(89\) |
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Time = 0.25 (sec) , antiderivative size = 70, normalized size of antiderivative = 1.01 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=\frac {4 \, \cos \left (f x + e\right )^{2} + 3 \, {\left (f x \cos \left (f x + e\right ) + f x\right )} \sin \left (f x + e\right ) + \cos \left (f x + e\right ) - 2}{3 \, {\left (a^{2} c f \cos \left (f x + e\right ) + a^{2} c f\right )} \sin \left (f x + e\right )} \]
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\[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=- \frac {\int \frac {1}{\sec ^{3}{\left (e + f x \right )} + \sec ^{2}{\left (e + f x \right )} - \sec {\left (e + f x \right )} - 1}\, dx}{a^{2} c} \]
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Time = 0.29 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.48 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=-\frac {\frac {\frac {12 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - \frac {\sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}}}{a^{2} c} - \frac {24 \, \arctan \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1}\right )}{a^{2} c} - \frac {3 \, {\left (\cos \left (f x + e\right ) + 1\right )}}{a^{2} c \sin \left (f x + e\right )}}{12 \, f} \]
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Time = 0.30 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.17 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=\frac {\frac {12 \, {\left (f x + e\right )}}{a^{2} c} + \frac {3}{a^{2} c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )} + \frac {a^{4} c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} - 12 \, a^{4} c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}{a^{6} c^{3}}}{12 \, f} \]
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Time = 13.96 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00 \[ \int \frac {1}{(a+a \sec (e+f x))^2 (c-c \sec (e+f x))} \, dx=\frac {x}{a^2\,c}+\frac {\frac {4\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4}{3}-\frac {7\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2}{6}+\frac {1}{12}}{a^2\,c\,f\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )} \]
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